Base | Representation |
---|---|
bin | 1100110111001000100111… |
… | …0011100100000010111011 |
3 | 1212001220021121020002002021 |
4 | 3031302021303210002323 |
5 | 3323142433122142021 |
6 | 50024235514415311 |
7 | 2656451460356026 |
oct | 315621163440273 |
9 | 55056247202067 |
10 | 14141344334011 |
11 | 4562346237874 |
12 | 170482b731537 |
13 | 7b76a51a434b |
14 | 36c63243c1bd |
15 | 197caeb6ac41 |
hex | cdc89ce40bb |
14141344334011 has 4 divisors (see below), whose sum is σ = 14373169651024. Its totient is φ = 13909519017000.
The previous prime is 14141344333979. The next prime is 14141344334027. The reversal of 14141344334011 is 11043344314141.
14141344334011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14141344334011 - 25 = 14141344333979 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14141344334081) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 115912658415 + ... + 115912658536.
It is an arithmetic number, because the mean of its divisors is an integer number (3593292412756).
Almost surely, 214141344334011 is an apocalyptic number.
14141344334011 is a deficient number, since it is larger than the sum of its proper divisors (231825317013).
14141344334011 is an equidigital number, since it uses as much as digits as its factorization.
14141344334011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 231825317012.
The product of its (nonzero) digits is 27648, while the sum is 34.
Adding to 14141344334011 its reverse (11043344314141), we get a palindrome (25184688648152).
The spelling of 14141344334011 in words is "fourteen trillion, one hundred forty-one billion, three hundred forty-four million, three hundred thirty-four thousand, eleven".
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