11043344314141 has 2 divisors, whose sum is σ = 11043344314142. Its totient is φ = 11043344314140.

The previous prime is 11043344314111. The next prime is 11043344314153. The reversal of 11043344314141 is 14141344334011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7330805342116 + 3712538972025 = 2707546^2 + 1926795^2 .

It is a cyclic number.

It is not a de Polignac number, because 11043344314141 - 2¹¹ = 11043344312093 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11043344314097 and 11043344314106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11043344314111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5521672157070 + 5521672157071.

It is an arithmetic number, because the mean of its divisors is an integer number (5521672157071).

Almost surely, 2^{11043344314141} is an apocalyptic number.

It is an amenable number.

11043344314141 is a deficient number, since it is larger than the sum of its proper divisors (1).

11043344314141 is an equidigital number, since it uses as much as digits as its factorization.

11043344314141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27648, while the sum is 34.

Adding to 11043344314141 its reverse (14141344334011), we get a palindrome (25184688648152).

The spelling of 11043344314141 in words is "eleven trillion, forty-three billion, three hundred forty-four million, three hundred fourteen thousand, one hundred forty-one".