Base | Representation |
---|---|
bin | 100000001001110101100010… |
… | …000011101000011101100011 |
3 | 200112200222211000020202212101 |
4 | 200021311202003220131203 |
5 | 122013404212443341011 |
6 | 1220432234455111231 |
7 | 41533532645324434 |
oct | 4011654203503543 |
9 | 615628730222771 |
10 | 141413443340131 |
11 | 41071117140996 |
12 | 13a3aa58072517 |
13 | 60ba2cc4c37b1 |
14 | 26cc6390a948b |
15 | 115374c9732c1 |
hex | 809d620e8763 |
141413443340131 has 2 divisors, whose sum is σ = 141413443340132. Its totient is φ = 141413443340130.
The previous prime is 141413443340107. The next prime is 141413443340153. The reversal of 141413443340131 is 131043344314141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 141413443340131 - 221 = 141413441242979 is a prime.
It is a super-2 number, since 2×1414134433401312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (141413443340831) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70706721670065 + 70706721670066.
It is an arithmetic number, because the mean of its divisors is an integer number (70706721670066).
Almost surely, 2141413443340131 is an apocalyptic number.
141413443340131 is a deficient number, since it is larger than the sum of its proper divisors (1).
141413443340131 is an equidigital number, since it uses as much as digits as its factorization.
141413443340131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 82944, while the sum is 37.
Adding to 141413443340131 its reverse (131043344314141), we get a palindrome (272456787654272).
The spelling of 141413443340131 in words is "one hundred forty-one trillion, four hundred thirteen billion, four hundred forty-three million, three hundred forty thousand, one hundred thirty-one".
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