141414113 has 2 divisors, whose sum is σ = 141414114. Its totient is φ = 141414112.

The previous prime is 141414103. The next prime is 141414167. The reversal of 141414113 is 311414141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 131629729 + 9784384 = 11473^2 + 3128^2 .

It is an emirp because it is prime and its reverse (311414141) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-141414113 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (141414103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70707056 + 70707057.

It is an arithmetic number, because the mean of its divisors is an integer number (70707057).

Almost surely, 2^141414113 is an apocalyptic number.

It is an amenable number.

141414113 is a deficient number, since it is larger than the sum of its proper divisors (1).

141414113 is an equidigital number, since it uses as much as digits as its factorization.

141414113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 192, while the sum is 20.

The square root of 141414113 is about 11891.7666055132. The cubic root of 141414113 is about 520.9918360354.

Adding to 141414113 its reverse (311414141), we get a palindrome (452828254).

The spelling of 141414113 in words is "one hundred forty-one million, four hundred fourteen thousand, one hundred thirteen".