Base | Representation |
---|---|
bin | 1000001110110101001… |
… | …0111101010001000011 |
3 | 111112000210220121112212 |
4 | 2003231102331101003 |
5 | 4304112022420303 |
6 | 144544552012335 |
7 | 13134344133122 |
oct | 2035522752103 |
9 | 445023817485 |
10 | 141420123203 |
11 | 54a80a77787 |
12 | 234a93910ab |
13 | 10449b67c98 |
14 | 6bb809bab9 |
15 | 3a2a73dad8 |
hex | 20ed4bd443 |
141420123203 has 2 divisors, whose sum is σ = 141420123204. Its totient is φ = 141420123202.
The previous prime is 141420123199. The next prime is 141420123227. The reversal of 141420123203 is 302321024141.
It is a weak prime.
It is an emirp because it is prime and its reverse (302321024141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 141420123203 - 22 = 141420123199 is a prime.
It is not a weakly prime, because it can be changed into another prime (141420123233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70710061601 + 70710061602.
It is an arithmetic number, because the mean of its divisors is an integer number (70710061602).
Almost surely, 2141420123203 is an apocalyptic number.
141420123203 is a deficient number, since it is larger than the sum of its proper divisors (1).
141420123203 is an equidigital number, since it uses as much as digits as its factorization.
141420123203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 141420123203 its reverse (302321024141), we get a palindrome (443741147344).
The spelling of 141420123203 in words is "one hundred forty-one billion, four hundred twenty million, one hundred twenty-three thousand, two hundred three".
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