1414206024141 has 4 divisors (see below), whose sum is σ = 1885608032192. Its totient is φ = 942804016092.

The previous prime is 1414206024107. The next prime is 1414206024157.

1414206024141 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1414206024141 - 2¹¹ = 1414206022093 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1414206024099 and 1414206024108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1414206024181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 235701004021 + ... + 235701004026.

It is an arithmetic number, because the mean of its divisors is an integer number (471402008048).

Almost surely, 2^{1414206024141} is an apocalyptic number.

It is an amenable number.

1414206024141 is a deficient number, since it is larger than the sum of its proper divisors (471402008051).

1414206024141 is an equidigital number, since it uses as much as digits as its factorization.

1414206024141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 471402008050.

The product of its (nonzero) digits is 6144, while the sum is 30.

The spelling of 1414206024141 in words is "one trillion, four hundred fourteen billion, two hundred six million, twenty-four thousand, one hundred forty-one".