141430213201153 has 4 divisors (see below), whose sum is σ = 144098707789908. Its totient is φ = 138761718612400.

The previous prime is 141430213201129. The next prime is 141430213201241. The reversal of 141430213201153 is 351102312034141.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 96161107355329 + 45269105845824 = 9806177^2 + 6728232^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-141430213201153 is a prime.

It is a super-2 number, since 2×141430213201153² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141430213501153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1334247294298 + ... + 1334247294403.

It is an arithmetic number, because the mean of its divisors is an integer number (36024676947477).

Almost surely, 2^{141430213201153} is an apocalyptic number.

It is an amenable number.

141430213201153 is a deficient number, since it is larger than the sum of its proper divisors (2668494588755).

141430213201153 is an equidigital number, since it uses as much as digits as its factorization.

141430213201153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2668494588754.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 141430213201153 its reverse (351102312034141), we get a palindrome (492532525235294).

The spelling of 141430213201153 in words is "one hundred forty-one trillion, four hundred thirty billion, two hundred thirteen million, two hundred one thousand, one hundred fifty-three".