141434124114341 has 4 divisors (see below), whose sum is σ = 141434285221152. Its totient is φ = 141433963007532.

The previous prime is 141434124114317. The next prime is 141434124114359. The reversal of 141434124114341 is 143411421434141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141434124114341 - 2²⁶ = 141434057005477 is a prime.

It is a super-3 number, since 3×141434124114341³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 141434124114295 and 141434124114304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141434124114841) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79229315 + ... + 80994768.

It is an arithmetic number, because the mean of its divisors is an integer number (35358571305288).

Almost surely, 2^{141434124114341} is an apocalyptic number.

It is an amenable number.

141434124114341 is a deficient number, since it is larger than the sum of its proper divisors (161106811).

141434124114341 is an equidigital number, since it uses as much as digits as its factorization.

141434124114341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 161106810.

The product of its digits is 73728, while the sum is 38.

Adding to 141434124114341 its reverse (143411421434141), we get a palindrome (284845545548482).

The spelling of 141434124114341 in words is "one hundred forty-one trillion, four hundred thirty-four billion, one hundred twenty-four million, one hundred fourteen thousand, three hundred forty-one".