Base | Representation |
---|---|
bin | 10100100101010000110… |
… | …101111011010110100011 |
3 | 12000012211000011202101122 |
4 | 110211100311323112203 |
5 | 141133143020220103 |
6 | 3001433332322455 |
7 | 204121110226454 |
oct | 24452065732643 |
9 | 5005730152348 |
10 | 1414400554403 |
11 | 4a593126aa21 |
12 | 1aa153a7342b |
13 | a34ba1bc795 |
14 | 4c658d8d12b |
15 | 26bd2515b38 |
hex | 14950d7b5a3 |
1414400554403 has 2 divisors, whose sum is σ = 1414400554404. Its totient is φ = 1414400554402.
The previous prime is 1414400554381. The next prime is 1414400554507. The reversal of 1414400554403 is 3044550044141.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1414400554403 is a prime.
It is not a weakly prime, because it can be changed into another prime (1414400553403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707200277201 + 707200277202.
It is an arithmetic number, because the mean of its divisors is an integer number (707200277202).
Almost surely, 21414400554403 is an apocalyptic number.
1414400554403 is a deficient number, since it is larger than the sum of its proper divisors (1).
1414400554403 is an equidigital number, since it uses as much as digits as its factorization.
1414400554403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 76800, while the sum is 35.
Adding to 1414400554403 its reverse (3044550044141), we get a palindrome (4458950598544).
The spelling of 1414400554403 in words is "one trillion, four hundred fourteen billion, four hundred million, five hundred fifty-four thousand, four hundred three".
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