Base | Representation |
---|---|
bin | 11010010110000110… |
… | …01011001100111011 |
3 | 1100111201110221021201 |
4 | 31023003023030323 |
5 | 212431332303103 |
6 | 10255255315031 |
7 | 1010334142444 |
oct | 151303131473 |
9 | 40451427251 |
10 | 14144025403 |
11 | 5aa8a2a6a2 |
12 | 28a897ba77 |
13 | 14453c8501 |
14 | 9826882cb |
15 | 57bad251d |
hex | 34b0cb33b |
14144025403 has 2 divisors, whose sum is σ = 14144025404. Its totient is φ = 14144025402.
The previous prime is 14144025367. The next prime is 14144025443. The reversal of 14144025403 is 30452044141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14144025403 - 225 = 14110470971 is a prime.
It is not a weakly prime, because it can be changed into another prime (14144025443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7072012701 + 7072012702.
It is an arithmetic number, because the mean of its divisors is an integer number (7072012702).
Almost surely, 214144025403 is an apocalyptic number.
14144025403 is a deficient number, since it is larger than the sum of its proper divisors (1).
14144025403 is an equidigital number, since it uses as much as digits as its factorization.
14144025403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7680, while the sum is 28.
Adding to 14144025403 its reverse (30452044141), we get a palindrome (44596069544).
The spelling of 14144025403 in words is "fourteen billion, one hundred forty-four million, twenty-five thousand, four hundred three".
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