14144034120331 has 2 divisors, whose sum is σ = 14144034120332. Its totient is φ = 14144034120330.

The previous prime is 14144034120289. The next prime is 14144034120361. The reversal of 14144034120331 is 13302143044141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14144034120331 - 2¹³ = 14144034112139 is a prime.

It is a super-2 number, since 2×14144034120331² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14144034120293 and 14144034120302.

It is not a weakly prime, because it can be changed into another prime (14144034120361) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7072017060165 + 7072017060166.

It is an arithmetic number, because the mean of its divisors is an integer number (7072017060166).

Almost surely, 2^{14144034120331} is an apocalyptic number.

14144034120331 is a deficient number, since it is larger than the sum of its proper divisors (1).

14144034120331 is an equidigital number, since it uses as much as digits as its factorization.

14144034120331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 14144034120331 its reverse (13302143044141), we get a palindrome (27446177164472).

The spelling of 14144034120331 in words is "fourteen trillion, one hundred forty-four billion, thirty-four million, one hundred twenty thousand, three hundred thirty-one".