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14144320023 = 34714773341
BaseRepresentation
bin11010010110001000…
…10011001000010111
31100111202000220102120
431023010103020113
5212431421220043
610255305511023
71010336510421
oct151304231027
940452026376
1014144320023
115aa9110a89
1228a8aa2473
13144549c642
14982723811
1557bb3e983
hex34b113217

14144320023 has 4 divisors (see below), whose sum is σ = 18859093368. Its totient is φ = 9429546680.

The previous prime is 14144320019. The next prime is 14144320027. The reversal of 14144320023 is 32002344141.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (14144320019) and next prime (14144320027).

It is a cyclic number.

It is not a de Polignac number, because 14144320023 - 22 = 14144320019 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14144319975 and 14144320002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14144320027) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2357386668 + ... + 2357386673.

It is an arithmetic number, because the mean of its divisors is an integer number (4714773342).

Almost surely, 214144320023 is an apocalyptic number.

14144320023 is a deficient number, since it is larger than the sum of its proper divisors (4714773345).

14144320023 is an equidigital number, since it uses as much as digits as its factorization.

14144320023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4714773344.

The product of its (nonzero) digits is 2304, while the sum is 24.

Adding to 14144320023 its reverse (32002344141), we get a palindrome (46146664164).

The spelling of 14144320023 in words is "fourteen billion, one hundred forty-four million, three hundred twenty thousand, twenty-three".

Divisors: 1 3 4714773341 14144320023