14144320141 has 4 divisors (see below), whose sum is σ = 16164937312. Its totient is φ = 12123702972.

The previous prime is 14144320139. The next prime is 14144320153. The reversal of 14144320141 is 14102344141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14144320141 - 2¹ = 14144320139 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14144320241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1010308575 + ... + 1010308588.

It is an arithmetic number, because the mean of its divisors is an integer number (4041234328).

Almost surely, 2^14144320141 is an apocalyptic number.

It is an amenable number.

14144320141 is a deficient number, since it is larger than the sum of its proper divisors (2020617171).

14144320141 is an equidigital number, since it uses as much as digits as its factorization.

14144320141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2020617170.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 14144320141 its reverse (14102344141), we get a palindrome (28246664282).

The spelling of 14144320141 in words is "fourteen billion, one hundred forty-four million, three hundred twenty thousand, one hundred forty-one".