Base | Representation |
---|---|
bin | 10100100101010010101… |
… | …111110011111010111110 |
3 | 12000012220020022001002212 |
4 | 110211102233303322332 |
5 | 141133224210134114 |
6 | 3001440433220422 |
7 | 204121645632446 |
oct | 24452257637276 |
9 | 5005806261085 |
10 | 1414432505534 |
11 | 4a5948303314 |
12 | 1aa162701712 |
13 | a34c39c8889 |
14 | 4c65d309126 |
15 | 26bd5227b3e |
hex | 14952bf3ebe |
1414432505534 has 16 divisors (see below), whose sum is σ = 2215666980000. Its totient is φ = 675926085120.
The previous prime is 1414432505413. The next prime is 1414432505537. The reversal of 1414432505534 is 4355052344141.
It is a super-2 number, since 2×14144325055342 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1414432505491 and 1414432505500.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1414432505537) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12251807 + ... + 12366714.
It is an arithmetic number, because the mean of its divisors is an integer number (138479186250).
Almost surely, 21414432505534 is an apocalyptic number.
1414432505534 is a deficient number, since it is larger than the sum of its proper divisors (801234474466).
1414432505534 is a wasteful number, since it uses less digits than its factorization.
1414432505534 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24619795.
The product of its (nonzero) digits is 576000, while the sum is 41.
Adding to 1414432505534 its reverse (4355052344141), we get a palindrome (5769484849675).
The spelling of 1414432505534 in words is "one trillion, four hundred fourteen billion, four hundred thirty-two million, five hundred five thousand, five hundred thirty-four".
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