1414441263341 has 4 divisors (see below), whose sum is σ = 1433817171132. Its totient is φ = 1395065355552.

The previous prime is 1414441263329. The next prime is 1414441263349. The reversal of 1414441263341 is 1433621444141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 419963618116 + 994477645225 = 648046^2 + 997235^2 .

It is a cyclic number.

It is not a de Polignac number, because 1414441263341 - 2³⁸ = 1139563356397 is a prime.

It is a super-2 number, since 2×1414441263341² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1414441263295 and 1414441263304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1414441263349) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9687953786 + ... + 9687953931.

It is an arithmetic number, because the mean of its divisors is an integer number (358454292783).

Almost surely, 2^{1414441263341} is an apocalyptic number.

It is an amenable number.

1414441263341 is a deficient number, since it is larger than the sum of its proper divisors (19375907791).

1414441263341 is an equidigital number, since it uses as much as digits as its factorization.

1414441263341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19375907790.

The product of its digits is 110592, while the sum is 38.

The spelling of 1414441263341 in words is "one trillion, four hundred fourteen billion, four hundred forty-one million, two hundred sixty-three thousand, three hundred forty-one".