Base | Representation |
---|---|
bin | 11010010110001101… |
… | …11100000010001011 |
3 | 1100111210100001102211 |
4 | 31023012330002023 |
5 | 212432110334401 |
6 | 10255332405551 |
7 | 1010345421415 |
oct | 151306740213 |
9 | 40453301384 |
10 | 14145011851 |
11 | 5aa9543843 |
12 | 28a91768b7 |
13 | 14456824c9 |
14 | 9828639b5 |
15 | 57bc29951 |
hex | 34b1bc08b |
14145011851 has 2 divisors, whose sum is σ = 14145011852. Its totient is φ = 14145011850.
The previous prime is 14145011821. The next prime is 14145011861. The reversal of 14145011851 is 15811054141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14145011851 - 233 = 5555077259 is a prime.
It is not a weakly prime, because it can be changed into another prime (14145011821) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7072505925 + 7072505926.
It is an arithmetic number, because the mean of its divisors is an integer number (7072505926).
Almost surely, 214145011851 is an apocalyptic number.
14145011851 is a deficient number, since it is larger than the sum of its proper divisors (1).
14145011851 is an equidigital number, since it uses as much as digits as its factorization.
14145011851 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3200, while the sum is 31.
Adding to 14145011851 its reverse (15811054141), we get a palindrome (29956065992).
The spelling of 14145011851 in words is "fourteen billion, one hundred forty-five million, eleven thousand, eight hundred fifty-one".
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