Base | Representation |
---|---|
bin | 1100110111010111000110… |
… | …0110100111011011010111 |
3 | 1212002021022121220200112202 |
4 | 3031311301212213123113 |
5 | 3323223414203112403 |
6 | 50030121435435115 |
7 | 2656650031552340 |
oct | 315656146473327 |
9 | 55067277820482 |
10 | 14145233254103 |
11 | 4563a61452016 |
12 | 1705535bb5a9b |
13 | 7b7b74aa2cb3 |
14 | 36c8c0b190c7 |
15 | 197e3b29d688 |
hex | cdd719a76d7 |
14145233254103 has 16 divisors (see below), whose sum is σ = 17188539863040. Its totient is φ = 11363534641536.
The previous prime is 14145233254091. The next prime is 14145233254129. The reversal of 14145233254103 is 30145233254141.
It is not a de Polignac number, because 14145233254103 - 238 = 13870355347159 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14145233254133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 248648351 + ... + 248705232.
It is an arithmetic number, because the mean of its divisors is an integer number (1074283741440).
Almost surely, 214145233254103 is an apocalyptic number.
14145233254103 is a deficient number, since it is larger than the sum of its proper divisors (3043306608937).
14145233254103 is a wasteful number, since it uses less digits than its factorization.
14145233254103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 497353846.
The product of its (nonzero) digits is 172800, while the sum is 38.
Adding to 14145233254103 its sum of digits (38), we get a palindrome (14145233254141).
The spelling of 14145233254103 in words is "fourteen trillion, one hundred forty-five billion, two hundred thirty-three million, two hundred fifty-four thousand, one hundred three".
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