Base | Representation |
---|---|
bin | 1000001110111101000… |
… | …0011101000010011101 |
3 | 111112010002211000022102 |
4 | 2003233100131002131 |
5 | 4304143433140331 |
6 | 144552125054445 |
7 | 13135223562062 |
oct | 2035720350235 |
9 | 445102730272 |
10 | 141453021341 |
11 | 54a985a7625 |
12 | 234b83b7425 |
13 | 10453916138 |
14 | 6bbc5c2c69 |
15 | 3a2d58b4cb |
hex | 20ef41d09d |
141453021341 has 4 divisors (see below), whose sum is σ = 141456993852. Its totient is φ = 141449048832.
The previous prime is 141453021323. The next prime is 141453021373. The reversal of 141453021341 is 143120354141.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 104035922116 + 37417099225 = 322546^2 + 193435^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-141453021341 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (141453021641) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1932356 + ... + 2004221.
It is an arithmetic number, because the mean of its divisors is an integer number (35364248463).
Almost surely, 2141453021341 is an apocalyptic number.
It is an amenable number.
141453021341 is a deficient number, since it is larger than the sum of its proper divisors (3972511).
141453021341 is an equidigital number, since it uses as much as digits as its factorization.
141453021341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3972510.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 141453021341 its reverse (143120354141), we get a palindrome (284573375482).
The spelling of 141453021341 in words is "one hundred forty-one billion, four hundred fifty-three million, twenty-one thousand, three hundred forty-one".
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