Base | Representation |
---|---|
bin | 1000010101001010100… |
… | …0110100101101011101 |
3 | 111200102022012021221002 |
4 | 2011102220310231131 |
5 | 4321102302313031 |
6 | 145425405520045 |
7 | 13224440636462 |
oct | 2052250645535 |
9 | 450368167832 |
10 | 143120354141 |
11 | 55773788416 |
12 | 238a2873025 |
13 | 1065b1956ab |
14 | 6cd9c03669 |
15 | 3ac9b3accb |
hex | 2152a34b5d |
143120354141 has 2 divisors, whose sum is σ = 143120354142. Its totient is φ = 143120354140.
The previous prime is 143120354131. The next prime is 143120354159. The reversal of 143120354141 is 141453021341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 115712227225 + 27408126916 = 340165^2 + 165554^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-143120354141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (143120354131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71560177070 + 71560177071.
It is an arithmetic number, because the mean of its divisors is an integer number (71560177071).
Almost surely, 2143120354141 is an apocalyptic number.
It is an amenable number.
143120354141 is a deficient number, since it is larger than the sum of its proper divisors (1).
143120354141 is an equidigital number, since it uses as much as digits as its factorization.
143120354141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 143120354141 its reverse (141453021341), we get a palindrome (284573375482).
The spelling of 143120354141 in words is "one hundred forty-three billion, one hundred twenty million, three hundred fifty-four thousand, one hundred forty-one".
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