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14145532220147 is a prime number
BaseRepresentation
bin1100110111011000001101…
…1011000101001011110011
31212002022002110110201212012
43031312003123011023303
53323230022222021042
650030211235353135
72656660321664426
oct315660333051363
955068073421765
1014145532220147
1145640a518a699
1217055ba1527ab
137b7bc19cb293
1436c90c6dd9bd
15197e57655e82
hexcdd836c52f3

14145532220147 has 2 divisors, whose sum is σ = 14145532220148. Its totient is φ = 14145532220146.

The previous prime is 14145532220111. The next prime is 14145532220269. The reversal of 14145532220147 is 74102223554141.

It is a weak prime.

It is an emirp because it is prime and its reverse (74102223554141) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14145532220147 is a prime.

It is a super-5 number, since 5×141455322201475 (a number of 67 digits) contains 55555 as substring.

It is not a weakly prime, because it can be changed into another prime (14145532220107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7072766110073 + 7072766110074.

It is an arithmetic number, because the mean of its divisors is an integer number (7072766110074).

Almost surely, 214145532220147 is an apocalyptic number.

14145532220147 is a deficient number, since it is larger than the sum of its proper divisors (1).

14145532220147 is an equidigital number, since it uses as much as digits as its factorization.

14145532220147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 268800, while the sum is 41.

Adding to 14145532220147 its reverse (74102223554141), we get a palindrome (88247755774288).

The spelling of 14145532220147 in words is "fourteen trillion, one hundred forty-five billion, five hundred thirty-two million, two hundred twenty thousand, one hundred forty-seven".