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14145535050433 is a prime number
BaseRepresentation
bin1100110111011000001110…
…0101111000001011000001
31212002022002122210112021121
43031312003211320023001
53323230023433103213
650030211420152241
72656660355023123
oct315660345701301
955068078715247
1014145535050433
1145640a6843076
1217055bb098681
137b7bc247c5c7
1436c90cc39213
15197e57a1488d
hexcdd839782c1

14145535050433 has 2 divisors, whose sum is σ = 14145535050434. Its totient is φ = 14145535050432.

The previous prime is 14145535050407. The next prime is 14145535050457. The reversal of 14145535050433 is 33405053554141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8275420150209 + 5870114900224 = 2876703^2 + 2422832^2 .

It is a cyclic number.

It is not a de Polignac number, because 14145535050433 - 237 = 14008096096961 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14145535050433.

It is not a weakly prime, because it can be changed into another prime (14145535050473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7072767525216 + 7072767525217.

It is an arithmetic number, because the mean of its divisors is an integer number (7072767525217).

Almost surely, 214145535050433 is an apocalyptic number.

It is an amenable number.

14145535050433 is a deficient number, since it is larger than the sum of its proper divisors (1).

14145535050433 is an equidigital number, since it uses as much as digits as its factorization.

14145535050433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1080000, while the sum is 43.

The spelling of 14145535050433 in words is "fourteen trillion, one hundred forty-five billion, five hundred thirty-five million, fifty thousand, four hundred thirty-three".