Base | Representation |
---|---|
bin | 100000001010110100100101… |
… | …100110001000010011100001 |
3 | 200112221110120111100201022211 |
4 | 200022310211212020103201 |
5 | 122021011343000400032 |
6 | 1220523313050402121 |
7 | 41541450515264365 |
oct | 4012644546102341 |
9 | 615843514321284 |
10 | 141481148450017 |
11 | 410978aa992062 |
12 | 13a4bbb2430341 |
13 | 60c37cc364aac |
14 | 26d1a1cdc32a5 |
15 | 11553b1871747 |
hex | 80ad259884e1 |
141481148450017 has 2 divisors, whose sum is σ = 141481148450018. Its totient is φ = 141481148450016.
The previous prime is 141481148449999. The next prime is 141481148450039. The reversal of 141481148450017 is 710054841184141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 86074622524881 + 55406525925136 = 9277641^2 + 7443556^2 .
It is a cyclic number.
It is not a de Polignac number, because 141481148450017 - 223 = 141481140061409 is a prime.
It is not a weakly prime, because it can be changed into another prime (141481148454017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70740574225008 + 70740574225009.
It is an arithmetic number, because the mean of its divisors is an integer number (70740574225009).
Almost surely, 2141481148450017 is an apocalyptic number.
It is an amenable number.
141481148450017 is a deficient number, since it is larger than the sum of its proper divisors (1).
141481148450017 is an equidigital number, since it uses as much as digits as its factorization.
141481148450017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 573440, while the sum is 49.
The spelling of 141481148450017 in words is "one hundred forty-one trillion, four hundred eighty-one billion, one hundred forty-eight million, four hundred fifty thousand, seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •