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14150052554401 is a prime number
BaseRepresentation
bin1100110111101001000011…
…0110110010011010100001
31212002201202111021111201101
43031322100312302122201
53323313301423220101
650032235554034401
72660210331125461
oct315722066623241
955081674244641
1014150052554401
114566004859725
12170645bb78a01
137b846237438a
1436cc1abbdba1
1519811e40e401
hexcde90db26a1

14150052554401 has 2 divisors, whose sum is σ = 14150052554402. Its totient is φ = 14150052554400.

The previous prime is 14150052554347. The next prime is 14150052554411. The reversal of 14150052554401 is 10445525005141.

14150052554401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8901719780625 + 5248332773776 = 2983575^2 + 2290924^2 .

It is a cyclic number.

It is not a de Polignac number, because 14150052554401 - 211 = 14150052552353 is a prime.

It is not a weakly prime, because it can be changed into another prime (14150052554411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7075026277200 + 7075026277201.

It is an arithmetic number, because the mean of its divisors is an integer number (7075026277201).

Almost surely, 214150052554401 is an apocalyptic number.

It is an amenable number.

14150052554401 is a deficient number, since it is larger than the sum of its proper divisors (1).

14150052554401 is an equidigital number, since it uses as much as digits as its factorization.

14150052554401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 80000, while the sum is 37.

Adding to 14150052554401 its reverse (10445525005141), we get a palindrome (24595577559542).

The spelling of 14150052554401 in words is "fourteen trillion, one hundred fifty billion, fifty-two million, five hundred fifty-four thousand, four hundred one".