Base | Representation |
---|---|
bin | 1100110111110000011100… |
… | …0110001110010100101011 |
3 | 1212002220212202001212001111 |
4 | 3031330013012032110223 |
5 | 3323331332243443423 |
6 | 50033204500531151 |
7 | 2660310436602415 |
oct | 315740706162453 |
9 | 55086782055044 |
10 | 14152036312363 |
11 | 4566932612414 |
12 | 17069143b0ab7 |
13 | 7b86ba352961 |
14 | 36cd6844b9b5 |
15 | 1981d866460d |
hex | cdf0718e52b |
14152036312363 has 2 divisors, whose sum is σ = 14152036312364. Its totient is φ = 14152036312362.
The previous prime is 14152036312343. The next prime is 14152036312367. The reversal of 14152036312363 is 36321363025141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14152036312363 - 25 = 14152036312331 is a prime.
It is not a weakly prime, because it can be changed into another prime (14152036312367) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7076018156181 + 7076018156182.
It is an arithmetic number, because the mean of its divisors is an integer number (7076018156182).
Almost surely, 214152036312363 is an apocalyptic number.
14152036312363 is a deficient number, since it is larger than the sum of its proper divisors (1).
14152036312363 is an equidigital number, since it uses as much as digits as its factorization.
14152036312363 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 233280, while the sum is 40.
The spelling of 14152036312363 in words is "fourteen trillion, one hundred fifty-two billion, thirty-six million, three hundred twelve thousand, three hundred sixty-three".
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