Base | Representation |
---|---|
bin | 11010010111000100… |
… | …00101011100111001 |
3 | 1100112021201121101111 |
4 | 31023202011130321 |
5 | 212440421101223 |
6 | 10300145120321 |
7 | 1010463051211 |
oct | 151342053471 |
9 | 40467647344 |
10 | 14152128313 |
11 | 6002564514 |
12 | 28ab6290a1 |
13 | 1446ca472b |
14 | 983797241 |
15 | 57c68330d |
hex | 34b885739 |
14152128313 has 2 divisors, whose sum is σ = 14152128314. Its totient is φ = 14152128312.
The previous prime is 14152128307. The next prime is 14152128349. The reversal of 14152128313 is 31382125141.
14152128313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12385018944 + 1767109369 = 111288^2 + 42037^2 .
It is a cyclic number.
It is not a de Polignac number, because 14152128313 - 25 = 14152128281 is a prime.
It is not a weakly prime, because it can be changed into another prime (14152128013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7076064156 + 7076064157.
It is an arithmetic number, because the mean of its divisors is an integer number (7076064157).
Almost surely, 214152128313 is an apocalyptic number.
It is an amenable number.
14152128313 is a deficient number, since it is larger than the sum of its proper divisors (1).
14152128313 is an equidigital number, since it uses as much as digits as its factorization.
14152128313 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5760, while the sum is 31.
The spelling of 14152128313 in words is "fourteen billion, one hundred fifty-two million, one hundred twenty-eight thousand, three hundred thirteen".
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