Base | Representation |
---|---|
bin | 10100100110001100011… |
… | …011000000011100011101 |
3 | 12000022101200001110210101 |
4 | 110212030123000130131 |
5 | 141142214413132313 |
6 | 3002120440541101 |
7 | 204154635413140 |
oct | 24461433003435 |
9 | 5008350043711 |
10 | 1415400130333 |
11 | 4a62a4524132 |
12 | 1aa392781791 |
13 | a361930b927 |
14 | 4c711a2a057 |
15 | 26c401615dd |
hex | 1498c6c071d |
1415400130333 has 4 divisors (see below), whose sum is σ = 1617600148960. Its totient is φ = 1213200111708.
The previous prime is 1415400130321. The next prime is 1415400130367. The reversal of 1415400130333 is 3330310045141.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1415400130333 - 213 = 1415400122141 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1415400130733) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 101100009303 + ... + 101100009316.
It is an arithmetic number, because the mean of its divisors is an integer number (404400037240).
Almost surely, 21415400130333 is an apocalyptic number.
It is an amenable number.
1415400130333 is a deficient number, since it is larger than the sum of its proper divisors (202200018627).
1415400130333 is an equidigital number, since it uses as much as digits as its factorization.
1415400130333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 202200018626.
The product of its (nonzero) digits is 6480, while the sum is 28.
Adding to 1415400130333 its reverse (3330310045141), we get a palindrome (4745710175474).
The spelling of 1415400130333 in words is "one trillion, four hundred fifteen billion, four hundred million, one hundred thirty thousand, three hundred thirty-three".
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