Base | Representation |
---|---|
bin | 11010010111010010… |
… | …11000110001010011 |
3 | 1100112102022212002111 |
4 | 31023221120301103 |
5 | 212441413324301 |
6 | 10300254130151 |
7 | 1010515242613 |
oct | 151351306123 |
9 | 40472285074 |
10 | 14154042451 |
11 | 600365164a |
12 | 28b01b0957 |
13 | 14474c4a63 |
14 | 983b34a43 |
15 | 57c910551 |
hex | 34ba58c53 |
14154042451 has 2 divisors, whose sum is σ = 14154042452. Its totient is φ = 14154042450.
The previous prime is 14154042437. The next prime is 14154042467. The reversal of 14154042451 is 15424045141.
14154042451 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14154042451 - 27 = 14154042323 is a prime.
It is not a weakly prime, because it can be changed into another prime (14154042401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7077021225 + 7077021226.
It is an arithmetic number, because the mean of its divisors is an integer number (7077021226).
Almost surely, 214154042451 is an apocalyptic number.
14154042451 is a deficient number, since it is larger than the sum of its proper divisors (1).
14154042451 is an equidigital number, since it uses as much as digits as its factorization.
14154042451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12800, while the sum is 31.
Adding to 14154042451 its reverse (15424045141), we get a palindrome (29578087592).
The spelling of 14154042451 in words is "fourteen billion, one hundred fifty-four million, forty-two thousand, four hundred fifty-one".
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