Base | Representation |
---|---|
bin | 11010010111010101… |
… | …10010100111010111 |
3 | 1100112110000112220021 |
4 | 31023222302213113 |
5 | 212442012113310 |
6 | 10300310050011 |
7 | 1010521334533 |
oct | 151352624727 |
9 | 40473015807 |
10 | 14154410455 |
11 | 6003883089 |
12 | 28b0349907 |
13 | 14475c3403 |
14 | 983bccbc3 |
15 | 57c9845da |
hex | 34bab29d7 |
14154410455 has 8 divisors (see below), whose sum is σ = 16989187104. Its totient is φ = 11320932000.
The previous prime is 14154410453. The next prime is 14154410461. The reversal of 14154410455 is 55401445141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 14154410455 - 21 = 14154410453 is a prime.
It is a super-2 number, since 2×141544104552 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 14154410455.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14154410453) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 300396 + ... + 344305.
It is an arithmetic number, because the mean of its divisors is an integer number (2123648388).
Almost surely, 214154410455 is an apocalyptic number.
14154410455 is a deficient number, since it is larger than the sum of its proper divisors (2834776649).
14154410455 is an equidigital number, since it uses as much as digits as its factorization.
14154410455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 649097.
The product of its (nonzero) digits is 32000, while the sum is 34.
Adding to 14154410455 its reverse (55401445141), we get a palindrome (69555855596).
The spelling of 14154410455 in words is "fourteen billion, one hundred fifty-four million, four hundred ten thousand, four hundred fifty-five".
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