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141550241321 = 671921067159
BaseRepresentation
bin1000001111010100001…
…1010100011000101001
3111112100212202022001102
42003311003110120221
54304343330210241
6145005520531145
713140514125206
oct2036503243051
9445325668042
10141550241321
115503846a415
1223524a80ab5
131046aac5458
146bcb48ccad
153a36d9239b
hex20f50d4629

141550241321 has 4 divisors (see below), whose sum is σ = 141571315200. Its totient is φ = 141529167444.

The previous prime is 141550241317. The next prime is 141550241333. The reversal of 141550241321 is 123142055141.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141550241321 - 22 = 141550241317 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141550241221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10526861 + ... + 10540298.

It is an arithmetic number, because the mean of its divisors is an integer number (35392828800).

Almost surely, 2141550241321 is an apocalyptic number.

It is an amenable number.

141550241321 is a deficient number, since it is larger than the sum of its proper divisors (21073879).

141550241321 is an equidigital number, since it uses as much as digits as its factorization.

141550241321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21073878.

The product of its (nonzero) digits is 4800, while the sum is 29.

Adding to 141550241321 its reverse (123142055141), we get a palindrome (264692296462).

The spelling of 141550241321 in words is "one hundred forty-one billion, five hundred fifty million, two hundred forty-one thousand, three hundred twenty-one".

Divisors: 1 6719 21067159 141550241321