Search a number
-
+
141550241317 is a prime number
BaseRepresentation
bin1000001111010100001…
…1010100011000100101
3111112100212202022001021
42003311003110120211
54304343330210232
6145005520531141
713140514125202
oct2036503243045
9445325668037
10141550241317
115503846a411
1223524a80ab1
131046aac5454
146bcb48cca9
153a36d92397
hex20f50d4625

141550241317 has 2 divisors, whose sum is σ = 141550241318. Its totient is φ = 141550241316.

The previous prime is 141550241297. The next prime is 141550241333. The reversal of 141550241317 is 713142055141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 141158755521 + 391485796 = 375711^2 + 19786^2 .

It is an emirp because it is prime and its reverse (713142055141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 141550241317 - 223 = 141541852709 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141550241377) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70775120658 + 70775120659.

It is an arithmetic number, because the mean of its divisors is an integer number (70775120659).

Almost surely, 2141550241317 is an apocalyptic number.

It is an amenable number.

141550241317 is a deficient number, since it is larger than the sum of its proper divisors (1).

141550241317 is an equidigital number, since it uses as much as digits as its factorization.

141550241317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16800, while the sum is 34.

Adding to 141550241317 its reverse (713142055141), we get a palindrome (854692296458).

The spelling of 141550241317 in words is "one hundred forty-one billion, five hundred fifty million, two hundred forty-one thousand, three hundred seventeen".