Base | Representation |
---|---|
bin | 11010010111011010… |
… | …11111111010110011 |
3 | 1100112111100121122002 |
4 | 31023231133322303 |
5 | 212442202322212 |
6 | 10300333204215 |
7 | 1010530352216 |
oct | 151355377263 |
9 | 40474317562 |
10 | 14155120307 |
11 | 6004218439 |
12 | 28b063066b |
13 | 14477b1543 |
14 | 983d3577d |
15 | 57ca74ac2 |
hex | 34bb5feb3 |
14155120307 has 2 divisors, whose sum is σ = 14155120308. Its totient is φ = 14155120306.
The previous prime is 14155120283. The next prime is 14155120339. The reversal of 14155120307 is 70302155141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14155120307 - 230 = 13081378483 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14155120307.
It is not a weakly prime, because it can be changed into another prime (14155120387) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7077560153 + 7077560154.
It is an arithmetic number, because the mean of its divisors is an integer number (7077560154).
Almost surely, 214155120307 is an apocalyptic number.
14155120307 is a deficient number, since it is larger than the sum of its proper divisors (1).
14155120307 is an equidigital number, since it uses as much as digits as its factorization.
14155120307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4200, while the sum is 29.
Adding to 14155120307 its reverse (70302155141), we get a palindrome (84457275448).
The spelling of 14155120307 in words is "fourteen billion, one hundred fifty-five million, one hundred twenty thousand, three hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •