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14155333045 = 571939120857
BaseRepresentation
bin11010010111011100…
…10011110110110101
31100112111202102110021
431023232103312311
5212442231124140
610300341525141
71010532226360
oct151356236665
940474672407
1014155333045
116004353257
1228b07137b1
131447857319
14983d8d0d7
1557cab7b4a
hex34bb93db5

14155333045 has 16 divisors (see below), whose sum is σ = 19414960128. Its totient is φ = 9705548160.

The previous prime is 14155333043. The next prime is 14155333079. The reversal of 14155333045 is 54033355141.

It is not a de Polignac number, because 14155333045 - 21 = 14155333043 is a prime.

It is a super-2 number, since 2×141553330452 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14155333045.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14155333043) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 668257 + ... + 689113.

It is an arithmetic number, because the mean of its divisors is an integer number (1213435008).

Almost surely, 214155333045 is an apocalyptic number.

It is an amenable number.

14155333045 is a deficient number, since it is larger than the sum of its proper divisors (5259627083).

14155333045 is a wasteful number, since it uses less digits than its factorization.

14155333045 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40260.

The product of its (nonzero) digits is 54000, while the sum is 34.

Adding to 14155333045 its reverse (54033355141), we get a palindrome (68188688186).

The spelling of 14155333045 in words is "fourteen billion, one hundred fifty-five million, three hundred thirty-three thousand, forty-five".

Divisors: 1 5 7 35 19391 20857 96955 104285 135737 145999 678685 729995 404438087 2022190435 2831066609 14155333045