Base | Representation |
---|---|
bin | 11010010111011101… |
… | …01010011110001001 |
3 | 1100112111221010111221 |
4 | 31023232222132021 |
5 | 212442242110143 |
6 | 10300343522041 |
7 | 1010533063414 |
oct | 151356523611 |
9 | 40474833457 |
10 | 14155425673 |
11 | 6004406904 |
12 | 28b0759321 |
13 | 144788a52c |
14 | 983db4b7b |
15 | 57cad52ed |
hex | 34bbaa789 |
14155425673 has 2 divisors, whose sum is σ = 14155425674. Its totient is φ = 14155425672.
The previous prime is 14155425611. The next prime is 14155425689. The reversal of 14155425673 is 37652455141.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13990868089 + 164557584 = 118283^2 + 12828^2 .
It is a cyclic number.
It is not a de Polignac number, because 14155425673 - 213 = 14155417481 is a prime.
It is not a weakly prime, because it can be changed into another prime (14155425373) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7077712836 + 7077712837.
It is an arithmetic number, because the mean of its divisors is an integer number (7077712837).
Almost surely, 214155425673 is an apocalyptic number.
It is an amenable number.
14155425673 is a deficient number, since it is larger than the sum of its proper divisors (1).
14155425673 is an equidigital number, since it uses as much as digits as its factorization.
14155425673 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 504000, while the sum is 43.
The spelling of 14155425673 in words is "fourteen billion, one hundred fifty-five million, four hundred twenty-five thousand, six hundred seventy-three".
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