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14160300643 is a prime number
BaseRepresentation
bin11010011000000010…
…10000101001100011
31100112212002210201101
431030001100221203
5213000014110033
610301040215231
71010622366226
oct151401205143
940485083641
1014160300643
116007136505
1228b230a517
1314488a6428
149848c35bd
1557d24997d
hex34c050a63

14160300643 has 2 divisors, whose sum is σ = 14160300644. Its totient is φ = 14160300642.

The previous prime is 14160300593. The next prime is 14160300647. The reversal of 14160300643 is 34600306141.

It is a strong prime.

It is an emirp because it is prime and its reverse (34600306141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14160300643 - 213 = 14160292451 is a prime.

It is a super-2 number, since 2×141603006432 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14160300647) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7080150321 + 7080150322.

It is an arithmetic number, because the mean of its divisors is an integer number (7080150322).

Almost surely, 214160300643 is an apocalyptic number.

14160300643 is a deficient number, since it is larger than the sum of its proper divisors (1).

14160300643 is an equidigital number, since it uses as much as digits as its factorization.

14160300643 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 14160300643 its reverse (34600306141), we get a palindrome (48760606784).

The spelling of 14160300643 in words is "fourteen billion, one hundred sixty million, three hundred thousand, six hundred forty-three".