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141634433 is a prime number
BaseRepresentation
bin10000111000100…
…10101110000001
3100212111202220202
420130102232001
5242224300213
622015414545
73336605243
oct1034225601
9325452822
10141634433
1172a49056
123b524455
1323460275
1414b4c093
15c67ab58
hex8712b81

141634433 has 2 divisors, whose sum is σ = 141634434. Its totient is φ = 141634432.

The previous prime is 141634369. The next prime is 141634447. The reversal of 141634433 is 334436141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 123032464 + 18601969 = 11092^2 + 4313^2 .

It is a cyclic number.

It is not a de Polignac number, because 141634433 - 26 = 141634369 is a prime.

It is a super-2 number, since 2×1416344332 = 40120625222462978, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 141634396 and 141634405.

It is not a weakly prime, because it can be changed into another prime (141634033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70817216 + 70817217.

It is an arithmetic number, because the mean of its divisors is an integer number (70817217).

Almost surely, 2141634433 is an apocalyptic number.

It is an amenable number.

141634433 is a deficient number, since it is larger than the sum of its proper divisors (1).

141634433 is an equidigital number, since it uses as much as digits as its factorization.

141634433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 10368, while the sum is 29.

The square root of 141634433 is about 11901.0265523609. The cubic root of 141634433 is about 521.2622601575.

The spelling of 141634433 in words is "one hundred forty-one million, six hundred thirty-four thousand, four hundred thirty-three".