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141642433 is a prime number
BaseRepresentation
bin10000111000101…
…00101011000001
3100212112011220001
420130110223001
5242230024213
622015520001
73336640462
oct1034245301
9325464801
10141642433
1172a54069
123b529001
1323463aba
1414b50d69
15c67d1dd
hex8714ac1

141642433 has 2 divisors, whose sum is σ = 141642434. Its totient is φ = 141642432.

The previous prime is 141642377. The next prime is 141642437. The reversal of 141642433 is 334246141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110817729 + 30824704 = 10527^2 + 5552^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-141642433 is a prime.

It is not a weakly prime, because it can be changed into another prime (141642437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70821216 + 70821217.

It is an arithmetic number, because the mean of its divisors is an integer number (70821217).

Almost surely, 2141642433 is an apocalyptic number.

It is an amenable number.

141642433 is a deficient number, since it is larger than the sum of its proper divisors (1).

141642433 is an equidigital number, since it uses as much as digits as its factorization.

141642433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6912, while the sum is 28.

The square root of 141642433 is about 11901.3626530746. The cubic root of 141642433 is about 521.2720742012.

Adding to 141642433 its reverse (334246141), we get a palindrome (475888574).

The spelling of 141642433 in words is "one hundred forty-one million, six hundred forty-two thousand, four hundred thirty-three".