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14164447603 is a prime number
BaseRepresentation
bin11010011000100010…
…00101000101110011
31100120010220111021111
431030101011011303
5213002044310403
610301305134151
71011002550415
oct151421050563
940503814244
1014164447603
116009509149
1228b378a357
1314496c8b57
149852829b5
1557d7b856d
hex34c445173

14164447603 has 2 divisors, whose sum is σ = 14164447604. Its totient is φ = 14164447602.

The previous prime is 14164447573. The next prime is 14164447621. The reversal of 14164447603 is 30674446141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14164447603 - 213 = 14164439411 is a prime.

It is not a weakly prime, because it can be changed into another prime (14164447403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7082223801 + 7082223802.

It is an arithmetic number, because the mean of its divisors is an integer number (7082223802).

Almost surely, 214164447603 is an apocalyptic number.

14164447603 is a deficient number, since it is larger than the sum of its proper divisors (1).

14164447603 is an equidigital number, since it uses as much as digits as its factorization.

14164447603 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 193536, while the sum is 40.

The spelling of 14164447603 in words is "fourteen billion, one hundred sixty-four million, four hundred forty-seven thousand, six hundred three".