Base | Representation |
---|---|
bin | 11010011000101111… |
… | …10111011001101001 |
3 | 1100120021020212111221 |
4 | 31030113313121221 |
5 | 213003023222122 |
6 | 10301411222041 |
7 | 1011023640001 |
oct | 151427673151 |
9 | 40507225457 |
10 | 14166226537 |
11 | 600a513741 |
12 | 28b42a7921 |
13 | 1449b9c788 |
14 | 9855c7001 |
15 | 57da1a6c7 |
hex | 34c5f7669 |
14166226537 has 2 divisors, whose sum is σ = 14166226538. Its totient is φ = 14166226536.
The previous prime is 14166226523. The next prime is 14166226567. The reversal of 14166226537 is 73562266141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12548256361 + 1617970176 = 112019^2 + 40224^2 .
It is a cyclic number.
It is not a de Polignac number, because 14166226537 - 231 = 12018742889 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14166226493 and 14166226502.
It is not a weakly prime, because it can be changed into another prime (14166226567) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7083113268 + 7083113269.
It is an arithmetic number, because the mean of its divisors is an integer number (7083113269).
Almost surely, 214166226537 is an apocalyptic number.
It is an amenable number.
14166226537 is a deficient number, since it is larger than the sum of its proper divisors (1).
14166226537 is an equidigital number, since it uses as much as digits as its factorization.
14166226537 is an evil number, because the sum of its binary digits is even.
The product of its digits is 362880, while the sum is 43.
The spelling of 14166226537 in words is "fourteen billion, one hundred sixty-six million, two hundred twenty-six thousand, five hundred thirty-seven".
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