Base | Representation |
---|---|
bin | 1000001111110101000… |
… | …0011111100000110111 |
3 | 111112201110210201102002 |
4 | 2003331100133200313 |
5 | 4310134101200003 |
6 | 145031315405515 |
7 | 13144105246004 |
oct | 2037520374067 |
9 | 445643721362 |
10 | 141687912503 |
11 | 550a9150855 |
12 | 23562bb389b |
13 | 104904987a7 |
14 | 6c018888ab |
15 | 3a43ed8a88 |
hex | 20fd41f837 |
141687912503 has 4 divisors (see below), whose sum is σ = 143063523408. Its totient is φ = 140312301600.
The previous prime is 141687912497. The next prime is 141687912551. The reversal of 141687912503 is 305219786141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 141687912503 - 26 = 141687912439 is a prime.
It is a super-3 number, since 3×1416879125033 (a number of 34 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (141687918503) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 687805298 + ... + 687805503.
It is an arithmetic number, because the mean of its divisors is an integer number (35765880852).
It is a 1-persistent number, because it is pandigital, but 2⋅141687912503 = 283375825006 is not.
Almost surely, 2141687912503 is an apocalyptic number.
141687912503 is a deficient number, since it is larger than the sum of its proper divisors (1375610905).
141687912503 is a wasteful number, since it uses less digits than its factorization.
141687912503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1375610904.
The product of its (nonzero) digits is 362880, while the sum is 47.
The spelling of 141687912503 in words is "one hundred forty-one billion, six hundred eighty-seven million, nine hundred twelve thousand, five hundred three".
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