14190140533 has 4 divisors (see below), whose sum is σ = 15024854700. Its totient is φ = 13355426368.

The previous prime is 14190140527. The next prime is 14190140579. The reversal of 14190140533 is 33504109141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8734397764 + 5455742769 = 93458^2 + 73863^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14190140533 is a prime.

It is a super-4 number, since 4×14190140533⁴ (a number of 42 digits) contains 4444 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14190140495 and 14190140504.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14190140593) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 417357058 + ... + 417357091.

It is an arithmetic number, because the mean of its divisors is an integer number (3756213675).

Almost surely, 2^14190140533 is an apocalyptic number.

It is an amenable number.

14190140533 is a deficient number, since it is larger than the sum of its proper divisors (834714167).

14190140533 is an equidigital number, since it uses as much as digits as its factorization.

14190140533 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 834714166.

The product of its (nonzero) digits is 6480, while the sum is 31.

Adding to 14190140533 its reverse (33504109141), we get a palindrome (47694249674).

The spelling of 14190140533 in words is "fourteen billion, one hundred ninety million, one hundred forty thousand, five hundred thirty-three".