Base | Representation |
---|---|
bin | 10100101010100101110… |
… | …000110100000001101111 |
3 | 12000202120121210002221111 |
4 | 110222211300310001233 |
5 | 141231401240304320 |
6 | 3004221053212451 |
7 | 204412621623352 |
oct | 24524560640157 |
9 | 5022517702844 |
10 | 1420120244335 |
11 | 4a82a69456a1 |
12 | 1ab28b491127 |
13 | a3bbc1929b0 |
14 | 4ca3c872299 |
15 | 26e1972da5a |
hex | 14aa5c3406f |
1420120244335 has 16 divisors (see below), whose sum is σ = 1835279982144. Its totient is φ = 1048676942592.
The previous prime is 1420120244297. The next prime is 1420120244341. The reversal of 1420120244335 is 5334420210241.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1420120244335 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1420120244297 and 1420120244306.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2437339 + ... + 2963251.
It is an arithmetic number, because the mean of its divisors is an integer number (114704998884).
Almost surely, 21420120244335 is an apocalyptic number.
1420120244335 is a deficient number, since it is larger than the sum of its proper divisors (415159737809).
1420120244335 is a wasteful number, since it uses less digits than its factorization.
1420120244335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 567474.
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 1420120244335 its reverse (5334420210241), we get a palindrome (6754540454576).
The spelling of 1420120244335 in words is "one trillion, four hundred twenty billion, one hundred twenty million, two hundred forty-four thousand, three hundred thirty-five".
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