Base | Representation |
---|---|
bin | 10100101010100101110… |
… | …000110100000001110101 |
3 | 12000202120121210002221201 |
4 | 110222211300310001311 |
5 | 141231401240304331 |
6 | 3004221053212501 |
7 | 204412621623361 |
oct | 24524560640165 |
9 | 5022517702851 |
10 | 1420120244341 |
11 | 4a82a69456a7 |
12 | 1ab28b491131 |
13 | a3bbc1929b6 |
14 | 4ca3c8722a1 |
15 | 26e1972da61 |
hex | 14aa5c34075 |
1420120244341 has 2 divisors, whose sum is σ = 1420120244342. Its totient is φ = 1420120244340.
The previous prime is 1420120244297. The next prime is 1420120244351. The reversal of 1420120244341 is 1434420210241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1022626562500 + 397493681841 = 1011250^2 + 630471^2 .
It is a cyclic number.
It is not a de Polignac number, because 1420120244341 - 223 = 1420111855733 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1420120244351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710060122170 + 710060122171.
It is an arithmetic number, because the mean of its divisors is an integer number (710060122171).
Almost surely, 21420120244341 is an apocalyptic number.
It is an amenable number.
1420120244341 is a deficient number, since it is larger than the sum of its proper divisors (1).
1420120244341 is an equidigital number, since it uses as much as digits as its factorization.
1420120244341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6144, while the sum is 28.
Adding to 1420120244341 its reverse (1434420210241), we get a palindrome (2854540454582).
The spelling of 1420120244341 in words is "one trillion, four hundred twenty billion, one hundred twenty million, two hundred forty-four thousand, three hundred forty-one".
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