14201212114 has 4 divisors (see below), whose sum is σ = 21301818174. Its totient is φ = 7100606056.

The previous prime is 14201212097. The next prime is 14201212117. The reversal of 14201212114 is 41121210241.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 41121210241 = 11887 ⋅3459343.

It can be written as a sum of positive squares in only one way, i.e., 12451212225 + 1749999889 = 111585^2 + 41833^2 .

It is a junction number, because it is equal to n+sod(n) for n = 14201212091 and 14201212100.

It is not an unprimeable number, because it can be changed into a prime (14201212117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3550303027 + ... + 3550303030.

Almost surely, 2^14201212114 is an apocalyptic number.

14201212114 is a deficient number, since it is larger than the sum of its proper divisors (7100606060).

14201212114 is an equidigital number, since it uses as much as digits as its factorization.

14201212114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7100606059.

The product of its (nonzero) digits is 128, while the sum is 19.

Adding to 14201212114 its reverse (41121210241), we get a palindrome (55322422355).

The spelling of 14201212114 in words is "fourteen billion, two hundred one million, two hundred twelve thousand, one hundred fourteen".