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142014113 = 197994613
BaseRepresentation
bin10000111011011…
…11011010100001
3100220020001201222
420131233122201
5242323422423
622031504425
73343046213
oct1035573241
9326201658
10142014113
117318833a
123b688115
1323564027
1414c0a5b3
15c7033c8
hex876f6a1

142014113 has 8 divisors (see below), whose sum is σ = 151382400. Its totient is φ = 132835248.

The previous prime is 142014109. The next prime is 142014133. The reversal of 142014113 is 311410241.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 142014113 - 22 = 142014109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 142014091 and 142014100.

It is not an unprimeable number, because it can be changed into a prime (142014133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 45806 + ... + 48807.

It is an arithmetic number, because the mean of its divisors is an integer number (18922800).

Almost surely, 2142014113 is an apocalyptic number.

It is an amenable number.

142014113 is a deficient number, since it is larger than the sum of its proper divisors (9368287).

142014113 is an equidigital number, since it uses as much as digits as its factorization.

142014113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 94711.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 142014113 is about 11916.9674414257. The cubic root of 142014113 is about 521.7276278534.

Adding to 142014113 its reverse (311410241), we get a palindrome (453424354).

The spelling of 142014113 in words is "one hundred forty-two million, fourteen thousand, one hundred thirteen".

Divisors: 1 19 79 1501 94613 1797647 7474427 142014113