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14202025330 = 251420202533
BaseRepresentation
bin11010011101000000…
…11011010101110010
31100122202121122020011
431032200123111302
5213041204302310
610305130405134
71011640136443
oct151640332562
940582548204
1014202025330
116028744919
1229042907aa
131454424cac
1498a2652ca
15581c3c78a
hex34e81b572

14202025330 has 8 divisors (see below), whose sum is σ = 25563645612. Its totient is φ = 5680810128.

The previous prime is 14202025283. The next prime is 14202025393. The reversal of 14202025330 is 3352020241.

14202025330 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 2 ways, for example, as 13005349681 + 1196675649 = 114041^2 + 34593^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-4 number, since 4×142020253304 (a number of 42 digits) contains 4444 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 710101257 + ... + 710101276.

Almost surely, 214202025330 is an apocalyptic number.

14202025330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

14202025330 is a deficient number, since it is larger than the sum of its proper divisors (11361620282).

14202025330 is a wasteful number, since it uses less digits than its factorization.

14202025330 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1420202540.

The product of its (nonzero) digits is 1440, while the sum is 22.

Adding to 14202025330 its reverse (3352020241), we get a palindrome (17554045571).

The spelling of 14202025330 in words is "fourteen billion, two hundred two million, twenty-five thousand, three hundred thirty".

Divisors: 1 2 5 10 1420202533 2840405066 7101012665 14202025330