Base | Representation |
---|---|
bin | 10100101010101100010… |
… | …011001010100110111001 |
3 | 12000202212021010212002112 |
4 | 110222230103022212321 |
5 | 141232112324204032 |
6 | 3004240011542105 |
7 | 204415423035206 |
oct | 24525423124671 |
9 | 5022767125075 |
10 | 1420229913017 |
11 | 4a8352840373 |
12 | 1ab30015a935 |
13 | a3c08b102c6 |
14 | 4ca4d25ccad |
15 | 26e241931b2 |
hex | 14aac4ca9b9 |
1420229913017 has 2 divisors, whose sum is σ = 1420229913018. Its totient is φ = 1420229913016.
The previous prime is 1420229912987. The next prime is 1420229913023. The reversal of 1420229913017 is 7103199220241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 782059004281 + 638170908736 = 884341^2 + 798856^2 .
It is a cyclic number.
It is not a de Polignac number, because 1420229913017 - 210 = 1420229911993 is a prime.
It is not a weakly prime, because it can be changed into another prime (1420229913077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710114956508 + 710114956509.
It is an arithmetic number, because the mean of its divisors is an integer number (710114956509).
Almost surely, 21420229913017 is an apocalyptic number.
It is an amenable number.
1420229913017 is a deficient number, since it is larger than the sum of its proper divisors (1).
1420229913017 is an equidigital number, since it uses as much as digits as its factorization.
1420229913017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54432, while the sum is 41.
The spelling of 1420229913017 in words is "one trillion, four hundred twenty billion, two hundred twenty-nine million, nine hundred thirteen thousand, seventeen".
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