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1420255035 = 325191661117
BaseRepresentation
bin101010010100111…
…0101111100111011
310122222110102122100
41110221311330323
510402041130120
6352532554443
750123653143
oct12451657473
93588412570
101420255035
116697736a1
12337782a23
13198320cc4
14d68a5923
1584a46490
hex54a75f3b

1420255035 has 24 divisors (see below), whose sum is σ = 2591344080. Its totient is φ = 717602112.

The previous prime is 1420254973. The next prime is 1420255043. The reversal of 1420255035 is 5305520241.

It is a happy number.

It is not a de Polignac number, because 1420255035 - 27 = 1420254907 is a prime.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 829704 + ... + 831413.

It is an arithmetic number, because the mean of its divisors is an integer number (107972670).

Almost surely, 21420255035 is an apocalyptic number.

1420255035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

1420255035 is a deficient number, since it is larger than the sum of its proper divisors (1171089045).

1420255035 is a wasteful number, since it uses less digits than its factorization.

1420255035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1661147 (or 1661144 counting only the distinct ones).

The product of its (nonzero) digits is 6000, while the sum is 27.

The square root of 1420255035 is about 37686.2711739965. The cubic root of 1420255035 is about 1124.0581509641.

Adding to 1420255035 its reverse (5305520241), we get a palindrome (6725775276).

The spelling of 1420255035 in words is "one billion, four hundred twenty million, two hundred fifty-five thousand, thirty-five".

Divisors: 1 3 5 9 15 19 45 57 95 171 285 855 1661117 4983351 8305585 14950053 24916755 31561223 74750265 94683669 157806115 284051007 473418345 1420255035