Base | Representation |
---|---|
bin | 10100101010110000100… |
… | …000001101101011000111 |
3 | 12000210001011212010002121 |
4 | 110222300200031223013 |
5 | 141232233403123221 |
6 | 3004251011350411 |
7 | 204420240365032 |
oct | 24526040155307 |
9 | 5023034763077 |
10 | 1420300442311 |
11 | 4a8389633043 |
12 | 1ab31b8b2407 |
13 | a3c1a605a0a |
14 | 4ca5877c019 |
15 | 26e2a475a41 |
hex | 14ab080dac7 |
1420300442311 has 4 divisors (see below), whose sum is σ = 1420352989432. Its totient is φ = 1420247895192.
The previous prime is 1420300442299. The next prime is 1420300442329. The reversal of 1420300442311 is 1132440030241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1420300442311 - 215 = 1420300409543 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1420300442371) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26232996 + ... + 26287081.
It is an arithmetic number, because the mean of its divisors is an integer number (355088247358).
Almost surely, 21420300442311 is an apocalyptic number.
1420300442311 is a deficient number, since it is larger than the sum of its proper divisors (52547121).
1420300442311 is an equidigital number, since it uses as much as digits as its factorization.
1420300442311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52547120.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 1420300442311 its reverse (1132440030241), we get a palindrome (2552740472552).
The spelling of 1420300442311 in words is "one trillion, four hundred twenty billion, three hundred million, four hundred forty-two thousand, three hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •