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1420301251334 = 27197514975073
BaseRepresentation
bin10100101010110000100…
…011010011001100000110
312000210001020101012212102
4110222300203103030012
5141232234110020314
63004251040552102
7204420250304510
oct24526043231406
95023036335772
101420301251334
114a838a035959
121ab320022632
13a3c1a82a024
144ca5890cbb0
1526e2a5855de
hex14ab08d3306

1420301251334 has 16 divisors (see below), whose sum is σ = 2447161551648. Its totient is φ = 605610684672.

The previous prime is 1420301251283. The next prime is 1420301251349. The reversal of 1420301251334 is 4331521030241.

It is a junction number, because it is equal to n+sod(n) for n = 1420301251297 and 1420301251306.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 257484779 + ... + 257490294.

It is an arithmetic number, because the mean of its divisors is an integer number (152947596978).

Almost surely, 21420301251334 is an apocalyptic number.

1420301251334 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

1420301251334 is a deficient number, since it is larger than the sum of its proper divisors (1026860300314).

1420301251334 is a wasteful number, since it uses less digits than its factorization.

1420301251334 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 514975279.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 1420301251334 its reverse (4331521030241), we get a palindrome (5751822281575).

The spelling of 1420301251334 in words is "one trillion, four hundred twenty billion, three hundred one million, two hundred fifty-one thousand, three hundred thirty-four".

Divisors: 1 2 7 14 197 394 1379 2758 514975073 1029950146 3604825511 7209651022 101450089381 202900178762 710150625667 1420301251334