14203113132 has 24 divisors (see below), whose sum is σ = 35689874416. Its totient is φ = 4370188608.

The previous prime is 14203113091. The next prime is 14203113139. The reversal of 14203113132 is 23131130241.

14203113132 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 14203113099 and 14203113108.

It is not an unprimeable number, because it can be changed into a prime (14203113139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 45522643 + ... + 45522954.

Almost surely, 2^14203113132 is an apocalyptic number.

14203113132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

14203113132 is an abundant number, since it is smaller than the sum of its proper divisors (21486761284).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14203113132 is a wasteful number, since it uses less digits than its factorization.

14203113132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 91045617 (or 91045615 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 14203113132 its reverse (23131130241), we get a palindrome (37334243373).

The spelling of 14203113132 in words is "fourteen billion, two hundred three million, one hundred thirteen thousand, one hundred thirty-two".